(1)/(x+1)^2-(2)/(x+1)+2=0

Solution for (1)/(x+1)^2-(2)/(x+1)+2=0 equation:

(1)/(x+1)^2-(2)/(x+1)+2=0


Domain of the equation: (x+1)^2!=0

x∈R



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R


We calculate fractions


(1*(x+1))/((x+1)^2*(x+1))+(-2*(x+1)^2)/((x+1)^2*(x+1))+2=0


We calculate terms in parentheses: +(1*(x+1))/((x+1)^2*(x+1)), so:

1*(x+1))/((x+1)^2*(x+1)

We multiply all the terms by the denominator


1*(x+1))

Back to the equation:

+(1*(x+1)))



We calculate terms in parentheses: +(-2*(x+1)^2)/((x+1)^2*(x+1)), so:

-2*(x+1)^2)/((x+1)^2*(x+1)

We multiply all the terms by the denominator


-2*(x+1)^2)

We multiply parentheses

-2x-

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)